MATH SOLVE

3 months ago

Q:
# What equation is graphed in this figure?y−4=−13(x+2)y−3=13(x+1)y+2=−3(x−1)y−5=3(x−1)Number graph that ranges from negative ten to ten on the x and y axes. A line passes through begin ordered pair zero comma two end ordered pair and begin ordered pair one comma five end ordered pair

Accepted Solution

A:

Answer:y − 5 = 3(x − 1) Step-by-step explanation:1.Calculate the slope of the line.
The equation for the slope of a straight line is
m = (y₂ - y₁)/(x₂ - x₁)
The line passes through (0, 2) and (1, 5).
m = (5 - 2)/[1 - 0] = 3/1 = 3
The slope of the line is 3.
2. Identify the graph
A and B are wrong, because the coefficients of x are 13.
C is wrong, because the coefficient of x (the slope) is -3.
D is correct, because the coefficient of x is +3.
The equation that is graphed is y − 5 = 3(x − 1).