MATH SOLVE

3 months ago

Q:
# Miki prepared two gallons of a beverage that contains tea and lemonade in the ratio tea:lemonade=3:1. If Miki then added one-half gallon of lemonade to the mixture, what was the ratio of tea to lemonade in the new mixture?

Accepted Solution

A:

Ratio of tea to lemonade in the new mixture is 3 : 2Solution:Given that volume of a beverage prepared by Miki containing tea and lemonade = 2 gallons
Ratio of tea and lemonade in beverage prepared by Miki = 3:1 Then Miki added one half of gallon of lemonade to the mixture. Need to determine ratio of tea and lemonade in the new mixture.
Lets first calculate volume of tea and volume of lemonade in old mixture that is the one before adding one half of gallon of lemonade.
Given ratio of tea and lemonade in old mixture = 3: 1 , means our of every four parts of mixture, 3 parts are of tea and 1 part is of lemonade.
[tex]=>\text { In old mixture, } \frac{3}{4} \text { is tea and } \frac{1}{4} \text { is lemonade. }[/tex][tex]\text { Volume of tea in old mixture }=\frac{3}{4} \times \text { volume of old mixture }=\frac{3}{4} \times 2 \text { gallons }=1.5 \text { gallons }[/tex][tex]\text { Volume of lemonade in old mixture }=\frac{1}{4} \times \text { volume of old mixture }=\frac{1}{4} \times 2 \text { gallons }=0.5 \text { gallons }[/tex]Given that one-half gallon of lemonade is added to old mixture to form new mixture.
So Volume of lemonade in new mixture = Volume of lemonade in old mixture + one half gallon = 0.5 + 0.5 = 1 gallon
As there is no change in volume of tea , so Volume of Tea in new mixture = Volume of tea in old mixture = 1.5 gallons
Ratio of tea : lemonade in new mixture = 1.5 : 1 = 3 : 2 Hence ratio of tea to lemonade in the new mixture is 3 : 2.